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61 lines
2.0 KiB
Python
61 lines
2.0 KiB
Python
import json
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def find_skills_without_efficient(json_data):
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"""
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分析JSON数据，找出所有设施中没有efficient字段的技能
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"""
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results = {}
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# 遍历所有设施
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for facility, facility_data in json_data.items():
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# 检查是否有skills字段
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if 'skills' in facility_data:
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skills_without_efficient = []
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# 遍历该设施的所有技能
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for skill_id, skill_data in facility_data['skills'].items():
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# 检查技能是否有efficient字段
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if 'efficient' not in skill_data:
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skill_info = {
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'id': skill_id,
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'name': skill_data.get('name', ['未知名称'])[0] # 取第一个名称
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}
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skills_without_efficient.append(skill_info)
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# 如果该设施有缺少efficient的技能，添加到结果中
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if skills_without_efficient:
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results[facility] = skills_without_efficient
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return results
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def main():
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try:
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with open('../../resource/infrast.json', 'r', encoding='utf-8') as file:
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data = json.load(file)
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except FileNotFoundError:
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print("未找到 infrast.json 文件")
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return
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except json.JSONDecodeError:
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print("错误：JSON 文件格式不正确")
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return
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# 分析数据
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missing_efficient_skills = find_skills_without_efficient(data)
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# 输出结果
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if not missing_efficient_skills:
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print("所有技能都有 efficient 字段")
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else:
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print("缺少 efficient 字段的技能：")
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print("=" * 50)
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for facility, skills in missing_efficient_skills.items():
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print(f"\n设施: {facility}")
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print("-" * 30)
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for skill in skills:
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print(f"技能 ID: {skill['id']}")
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print(f"技能名称: {skill['name']}")
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print()
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main() |